Respuesta :

Willchemistry
mass of solute  in g :

1 kg ---------- 1000 g
0.098 kg ------ ??

0.098 x 1000 / 1 => 98.0 g

mass of solvent = 500.0 g 

Therefore:

% ( w/w ) = 98.0 / 98.0 + 500.0

% (w/w ) = 98.0 / 598.0

0.163 x 100 =>  16.3 %

Answer: The percentage concentration by mass of a solution that contains 0.098 kg of [tex]H_2SO_4[/tex] in 500.0 g of [tex]H_2O[/tex] is 16.4%

Explanation:

To calculate the mass percentage ,we use the formula:

[tex]\text{Mass percent}=\frac{\text{Mass of} H_2SO_4}{\text{Molar mass of} H_2SO_4+mass of water}\times 100[/tex]

Mass of [tex]H_2SO_4[/tex] = 0.098 kg= 98 g

Mass of water = 500 g

Putting values in above equation, we get:

[tex]\text{Mass percent}=\frac{98g}{98+500}\times 100=16.4\%[/tex]

Hence, percentage concentration by mass of a solution that contains 0.098 kg of [tex]H_2SO_4[/tex] in 500.0 g of [tex]H_2O[/tex] is 16.4%

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