A triangle has base b centimeters and height h centimeters, where the height is three times the base. Both b and h are functions of time t, measured in seconds. If A represents the area of the triangle, what gives the rate of change of A with respect to t?

Respuesta :

The rate of change of A with respect to t is dA/dt = 9b(t)

Given the following parameters

  • Base of a triangle is b
  • h is the height of a triangle;
  • A is the area of the triangle

If the height is three times the base, then h(t) = 3b(t)

If b and h are functions of "t

The formula for finding the area of a triangle is expressed as:

A = 0.5b(t)h(t)

A = 0.5b(t)3b(t)

A = 4.5b(t)²

The rate of change of the area is expressed as:

dA/dt = 2(4.5)b(t)

dA/dt = 9b(t)

Hence the rate of change of A with respect to t is dA/dt = 9b(t)

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