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It takes pump A 2 hours less time that pump B to empty a swimming pool. Pump A is started at 8:00 a.m. and pump B is started at 10:00 a.m. At 12:00 p.m. 60% of the pool is empty when pump B broke down. How much time after 12:00 p.m. would it take pump A to empty the pool?

Respuesta :

Answer:

HERE YOU GO

Step-by-step explanation:

x2 - 4x + 2 + y2 - 4y + 2 = 4 : expand equation of first circle

x2 - 2x + 1 + y2 - 2y + 1 = 4 : expand equation of second circle

-2x - 2y - 6 = 0 : subtract the left and right terms of the above equations

y = 3 - x : solve the above for y.

2x2 - 6x + 1 = 0 : substitute y by 3 - x in the first equation, expand and group like terms.

(3/2 + √(7)/2 , 3/2 - √(7)/2) , (3/2 - √(7)/2 , 3/2 + √(7)/2) : solve the above for x and use y = 3 - x to find y.

Answer:

5/3 hours   or 1 hour and 40 minutes

Step-by-step explanation: