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A carnival game is played by rolling a ball into a hole. Eight players are needed to play the game and the top three places win raffle tickets.
The first place finisher wins 3 tickets, the second-place winner
wins two tickets and the third-place finisher wins one ticket. Which of the
following expressions gives the number of different ways there are for the three winners be selected from the eight players?
OaP3
Ob BPS
Ος
8C3
Od
8C

A carnival game is played by rolling a ball into a hole Eight players are needed to play the game and the top three places win raffle tickets The first place fi class=

Respuesta :

Using the concepts of permutation and combination, it is found that the number of different ways there are for the three winners be selected from the eight players is:

[tex]P_{8,3}[/tex], given by option A.

  • If the order is important, permutation is used, and the number of permutations of x elements from a set of n is given by: [tex]P_{n,x}[/tex].
  • If the order is not important, combination is used, and the number of combinations of x elements from a set of n is given by: [tex]C_{n,x}[/tex].

In this problem, the order is important, as the rank of the 3 winners determine the number of tickets each of them end up with, hence, permutation is used.

There are 3 winners from a set of 8, hence, the number of ways is:

[tex]P_{8,3}[/tex], given by option A.

To learn more about permutation and combination, you can take a look at https://brainly.com/question/25925367

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