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In a lab experiment, 5300 bacteria are placed in a petri dish. The conditions are such
that the number of bacteria is able to double every 23 hours. How long would it be, to
the nearest tenth of an hour, until there are 10500 bacteria present?

Respuesta :

makalaidavis88

Answer: x = 22.7

Step-by-step explanation:Based on the given conditions, formulate: 5300x2(x divided by 23) = 10500

Divide both sides of the equation by the coefficient of variable: 2 x/23 = 10500/5300

Reduce the fraction:2 x/23 = 105/53

Convert exponential to logarithm form: x/23 = long^2 105/53

Divide both sides of the equation by the coefficient of variable:x = log^2 105/53 x 23

Rewrite the expression: x = 23 long^2 105/53

Round the number: x = 22.7

Answer: x = 22.7

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