The solution of the given equation x² - 4x + 1 = 0 is;
x = 2 ± √3
We are given;
x² - 4x + 1 = 0
Using quadratic formula we have;
x = [-b ± √b² - 4ac]/2a
where;
a = 1
b = -4
c = 1
Thus;
x = [-(-4) ± √((-4)² - 4(1 * 1)]/2(1)
x = (4 ± √(16 - 4))/2
x = (4 ± √12)/2
x = (4 ± 2√3)/2
x = 2 ± √3
Read more on quadratic equations at; https://brainly.com/question/8649555
