Changes made to your input should not affect the solution:
Changes made to your input should not affect the solution: (1): "x2" was replaced by "x^2". 1 more similar replacement(s).
x3+x2-8x-12 is not a perfect cube
Factoring: x3+x2-8x-12
Thoughtfully split the expression at hand into groups, each group having two terms :
Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: x3+x2
Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: x3+x2 Group 2: -8x-12
Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: x3+x2 Group 2: -8x-12 Pull out from each group separately :
Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: x3+x2 Group 2: -8x-12 Pull out from each group separately :Group 1: (x+1) • (x2)
Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: x3+x2 Group 2: -8x-12 Pull out from each group separately :Group 1: (x+1) • (x2)Group 2: (2x+3) • (-4)
