contestada

13. The sum of four consecutive odd integers is 216. Which equation can

be used to solve for the smallest of the integers, x?


A. X + (x + 1) + (x + 2)+ (x + 3) = 216


B. x + (x + 1) + (x + 3) + (x + 5) = 216


C. X + (x + 2) + (x + 3) + (x + 4) = 216


Option 6


D. X +( x + 2 )+ (x + 4) +(x + 6) = 216

Respuesta :

namwanjemacklineeliz

Answer:

D .X +(X+2)+(X+4)+(X+6)=216

The numbers are 51, 53, 55, 57 giving 216

Step-by-step explanation:

HOPE THAT THIS IS HELPFUL.

HAVE A GREAT DAY.

Otras preguntas