Respuesta :
Answer:
[tex]x = -4[/tex]
Step-by-step explanation:
As I was taught in Algebra class, we use the distributive property to solve this, although there are other ways.
[tex]3(x+2)-7 = 5x + 7[/tex]
Step 1: Distribute.
We are going to distribute 3 to [tex]x[/tex] and +2 (positive 2). Which means multiplying 3 to [tex]x[/tex] and 2.
[tex]3(x+2)\\3\cdot x = 3x\\3\cdot 2 = 6\\\\= 3x+6[/tex]
So, therefore, we have [tex]3x+6-7=5x+7[/tex]
Step 2: Combine like terms.
Combining like terms simply means adding, values that are alike. For example, we can only add [tex]x[/tex] and [tex]x[/tex], [tex]y[/tex] and [tex]y[/tex], or a number and another number. Note, we can only combine like terms on one side of the equation, meaning at the end of the equal to sign.
[tex]3x+\bold6\:\:\bold-\bold7=5x+7[/tex]
Here we have +6 and -7, so adding those two would result in -1
So, therefore, we have [tex]3x-1=5x+7[/tex]
Step 3: Solve for [tex]x[/tex]
[tex]3x-1=5x+7[/tex]
- Subtract both sides by 7
[tex]3x-1=5x+7\\\:\:\:\:-7\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:-7[/tex]
7 - 7 = 0, so it cancels that side out.
-1 + 7 = -8, so we are left with;
[tex]3x-8=5x[/tex]
- Subtract 3[tex]\bold x[/tex] from both sides
[tex]3x-8=5x\\-3\:\:\:\:\:\:-3x[/tex]
3x - 3x = 0, so it cancels that side out.
5 - 3 = -2, so we are left with;
[tex]-8=2x[/tex]
- Divide both sides by 2
[tex]\frac{2x}{2}=\frac{-8}{2}[/tex]
2 over 2 cancels out
[tex]\frac{-8}{2} = -4[/tex]
