Answer:
Solution
(f+g)(x)=f(x)+g(x)
=x
2
+2x+1
(f−g)(x)=f(x)−g(x)
−(2x+1)
−2x−1
(fg)(x)=f(x).g(x)
(2x+1)
=2x
3
+x
(
g
f
)(x)=
g(x)
f(x)
(g(x)
=0)
=
2x+1
x
(x
=−
1
)
Step-by-step explanation:
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