The number of atoms present in 0.231 g of sodium is 6.02 x 10²¹ atoms.
The given parameters;
- mass of the reacting sodium = 0.231 g
- 1 mole of an atom = 6.02 x 10²³ atoms
- the atomic mass of sodium is 23 g/mol
The number of moles of 0.231 g of sodium available is calculated as;
[tex]no. \ of \ moles = \frac{Reacting \ mass}{Molar \ mass} \\\\no. \ of \ moles = \frac{0.231}{23} \\\\no. \ of \ moles = 0.01 \ mol.[/tex]
The number of atoms of 0.01 mole of sodium available is calculated as;
1 mole ---------- 6.02 x 10²³ atoms
0.01 ----------------- ?
= 0.01 x 6.02 x 10²³ atoms
= 6.02 x 10²¹ atoms.
Thus, the number of atoms present in 0.231 g of sodium is 6.02 x 10²¹ atoms.
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