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In the attached position versus time graph what is the magnitude of average velocity for the entire 19 seconds of the motion. Answer in m/s and the number only to the
nearest 100th (ie. The second position after the decimal point.). Remind yourself of the definition of velocity.

In the attached position versus time graph what is the magnitude of average velocity for the entire 19 seconds of the motion Answer in ms and the number only to class=

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LammettHash

According to the plot, the positions at time t = 0 s and t = 19 s are -1 m and -2 m, respectively. So the average velocity for the 19-s interval is

[tex]v_{\rm ave} = \dfrac{-2\,\mathrm m - (-1\,\mathrm m)}{19\,\mathrm s} = -\dfrac1{19}\dfrac{\rm m}{\rm s}\approx \boxed{-0.05\dfrac{\rm m}{\rm s}}[/tex]

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