Help on 1&2 please!!

Answer:
1. 25
2. 7
Step-by-step explanation:
Let the variables be denoted as "x".
1. If 5 times "x" is increased by 50, the result is the same as when 200 is decreased by "x".
Set the equation:
5x + 50 = 200 - x
Isolate the x. Note the equal sign, what you do to one side, you do to the other. First, add x and subtract 50 from both sides:
5x (+ x) + 50 (-50) = 200 (-50) - x (+x)
5x + x = 200 - 50
6x = 150
Next, divide 6 from both sides of the equation:
(6x)/6 = (150)/6
x = 150/6 = 25
25 is your number.
~
2. If 50 is decreased by 4 times "x", the result is 15 more than "x".
Set the equation:
50 - 4x = 15 + x
Isolate the x. Note the equal sign, what you do to one side, you do to the other. First, subtract x and subtract 50 from both sides:
50 (-50) - 4x (-x) = 15 (-50) + x (-x)
-4x - x = 15 - 50
-5x = -35
Divide -5 from both sides of the equation:
(-5x)/-5 = (-35)/-5
x = -35/-5 = 7
x = 7
7 is your number.
~
Answer:
#1) x=25, #2) x=7
Step-by-step explanation:
Number One:
We will replace this "number" with the variable "x".
"5 times a number.." gives us 5x.
"...increased by 50" gives us 5x+50.
5x+50
"The result is the same as when 200 is decreased by the number." gives us 200-x.
Now, we have a complete equation.
5x+50=200-x
1) To solve this, first subtract 50 from both sides.
5x=150-x
2) Add the x on both sides.
5x+x=150
3) Combine like terms.
6x=150
4) Divide by 6 on both sides.
x=25
Number Two:
Once again, lets use "x" as the number.
"If 50 is decreased by 4 times a certain number..." gives us 50-4x.
"...the result is 15 more than the number." gives us x+15.
Now, we have another complete equation! :)
50-4x=x+15
1) Subtract 15 from both sides.
35-4x=x
2) Add 4x to both sides.
35=x+4x
3) Combine like terms.
35=5x
4) Divide by 5 on both sides.
x=7
That's it! I hope this helped :)