Answer:
B. 4
Step-by-step explanation:
Given,
[tex] {x}^{8} = {( {2}^{2} )}^{4} [/tex]
Since,
[tex] { ({a}^{x} )}^{y} = {a}^{xy} [/tex]
Then,
[tex] = > {x}^{8} = {2}^{2 \times 4} [/tex]
[tex] = > {x}^{8} = {2}^{8} [/tex]
(Since the exponents are same so the bases will be also same)
Therefore,
=> x = 2
As per condition,
[tex] {x}^{2} [/tex]
(Putting value of x = 2)
[tex] ={2}^{2} [/tex]
= 4 (Ans)
