Respuesta :

susanwiederspan
It's easiest to start with the point-slope form of an equation, [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1, y_1)[/tex] is the point given.

We have m = 3, [tex]x_1 = 5[/tex], and [tex]y_1 = 10[/tex].

We plug in these values to get
[tex]y-10=3(x-5)[/tex].

We now rearrange to get this into slope-intercept form, [tex]y=mx+b[/tex], by solving for y.

[tex]y=3(x-5)+10\\y=3x-15[/tex]
Louli
Answer:
y = 3x - 5

Explanation:
The equation of the line in slope-intercept form is:
y = mx + c
where:
m is the slope
c is the y-intercept

We are given that the slope is 3. Therefore, the equation now is:
y = 3x + c

Now, we need to get the value of c. To do so, we will substitute with the given point (5,10) in the equation and solve for c as follows:
y = 3x + c
10 = 3(5) + c
10 = 15 + c
c = 10 - 15
c = -5

Based on the above, the equation of the line is:
y = 3x - 5

Hope this helps :)