Find the probability that a randomly
selected point within the circle falls
in the white area.
r = 4 cm
2.5 cm
3 cm
3 cm
[?]%
Round to the nearest tenth of a percent.

Find the probability that a randomly selected point within the circle falls in the white area r 4 cm 25 cm 3 cm 3 cm Round to the nearest tenth of a percent class=

Respuesta :

Answer:

61.2%

Step-by-step explanation:

Area of the circle π(4²) = 50.265... cm²

Area of the triangle = ½(6)(6.5) = 19.5 cm²

probability of landing is white is

1 - (19.5 / 50.265) = 0.612059...

The probability that a randomly selected point within the circle falls in the white area is 61.22%.

What is probability?

It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

As we know the circle is a set of points, where each point is at the same distance from a fixed point (called the center of a circle)

The total outcomes = The area of a circle

The area of the circle = πr²

The area of the circle = π(4)²

Because r = 4 cm

The area of the circle = 50.285 square cm

The area of the triangle = (1/2)(3+3)(4+2.5)

The area of the triangle = 19.5 square cm

The area of the white region = 50.285 - 19.5 = 30.785 square cm

Probability = 30.785/50.285

Probability = 0.6122 or

Probability = 61.22%

Thus, the probability that a randomly selected point within the circle falls in the white area is 61.22%.

Learn more about the probability here:

brainly.com/question/11234923

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