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PLEASE HELP!!!


The distance d of a particle moving in a straight line is given by d(t) = 2t^3 + 5t – 2, where t is given in seconds and d is measured in meters.



Find the velocity of the particle for t = 7 seconds.


A) 152 m/s


B) 47 m/s


C) 733 m/s


D) 299 m/s

Respuesta :

20100024120017

Answer:

The derivative of the position function gives the velocity function

 

2 t^3 + 5 t -2    derivative   =   6 t^2 + 5

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