Answer:
G is the midpoint of the side [tex]\overline {AB}[/tex] of triangle ΔOAB
Step-by-step explanation:
The vertices of the triangle ΔOAB are A(-15, 0), B(0, 8), and C(0, 0)
The coordinates of the point G = (-7.5, 4)
The length from the point A to the point G, [tex]\overline {AG}[/tex] is given as follows;
[tex]\overline {AG} =\sqrt{(-7.5 - (-15))^2 + (4 - 0)^2} = \sqrt{7.5^2 + 4^2} = 8.5[/tex]
The length from the point A to the point B, [tex]\overline {AB}[/tex] is given as follows;
[tex]\overline {AB} =\sqrt{(-15 - 0)^2 + (8 - 0)^2} = \sqrt{15^2 + 8^2} = 17[/tex]
Therefore, the point G is the half way mark of [tex]\overline {AB}[/tex] = The midpoint of the side [tex]\overline {AB}[/tex]
