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when simplifying the expression y=(2x(x-3)(x-3))/(x-1)(x-3) do all of the x-3 s get cancelled or just one in the numerator and one in the denominator?​

when simplifying the expression y2xx3x3x1x3 do all of the x3 s get cancelled or just one in the numerator and one in the denominator class=

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lieslgeissler

Answer:

Just one of the ones in the numerator and the one in the denominator

Step-by-step explanation:

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