Answer:
[D] ∞
General Formulas and Concepts:
Calculus
Limits
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle \lim_{n \to \infty} s(n)[/tex]
[tex]\displaystyle s(n) = (\frac{5}{4n^4})(3n^5 + 3n^4 + 2n^3 + n^2)[/tex]
Step 2: Evaluate
- Substitute in function [Limit]: [tex]\displaystyle \lim_{n \to \infty} (\frac{5}{4n^4})(3n^5 + 3n^4 + 2n^3 + n^2)[/tex]
- Multiply: [tex]\displaystyle \lim_{n \to \infty} \frac{5(3n^5 + 3n^4 + 2n^3 + n^2)}{4n^4}[/tex]
- Power Method: [tex]\displaystyle \lim_{n \to \infty} \frac{5(3n^5 + 3n^4 + 2n^3 + n^2)}{4n^4} = \infty[/tex]
Since the degree of the polynomial is greater in the numerator than in the denominator, the top will always increase faster than the bottom, thus getting infinitely larger.
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Limits
Book: College Calculus 10e
