The given equation has been solved in the table.
Step
Statement
1
fr – 9 = -13
RO
2
2
31
et – 9 + 9 = -13
+ 9
2
ਤੇ
3
3 = -4
3 2
3
3 .(-4)
2.32
5
6
in which step was the addition property of equality applied?

The given equation has been solved in the table Step Statement 1 fr 9 13 RO 2 2 31 et 9 9 13 9 2 ਤ 3 3 4 3 2 3 3 4 232 5 6 in which step was the addition proper class=