Answer:
Not a solution
Step-by-step explanation:
In order for [tex]x=-2[/tex] to be a solution, the result after substituting must be 0:
[tex]4(-2)^3-(-2)^2+16(-2)-4\stackrel{?}{=}0[/tex]
[tex]4(-8)-4-32-4\stackrel{?}{=}0[/tex]
[tex]-32-40\stackrel{?}{=}0[/tex]
[tex]-72\neq0[/tex]
Therefore, [tex]x=-2[/tex] is not a solution to [tex]4x^3-x^2+16x-4[/tex]
