Answer:
P = 100 lb
Explanation:
For an ideal machine:
[tex]Work\ In = Work\ Out\\(P)(L)=(W)(H)[/tex]
where,
P = Effort = Input Force = ?
L = Effort Arm = Length of inclined plane = 10 ft
W = Load to be lifted = 200 lb
H = Load Arm = Height = 5 ft
Therefore,
[tex]P(10\ ft) = (200\ lb)(5\ ft)\\\\P = \frac{(200\ lb)(5\ ft)}{10\ ft}[/tex]
P = 100 lb