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Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 4.78 mL of O2 had passed through the membrane, but only 3.21 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas

Respuesta :

Answer: The molar mass of the unknown gas is 71 g/mol

Explanation:

Graham's Law states that the rate of diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

[tex]Rate=\frac{1}{\sqrt {\text { Molar mass}}}[/tex]

[tex]\frac{R_1}{R_2}=\sqrt \frac{M_2}{M_1}[/tex]

Putting the values we get :

[tex]\frac{R_{O_2}}{R_X}=\sqrt \frac{M_X}{M_O_2}[/tex]

[tex]\frac{4.78}{3.21}=\sqrt \frac{M_X}{32g/mol}[/tex]

[tex]M_X=71g/nol[/tex]

Thus molar mass of the unknown gas is 71 g/mol