The distance of a train from the city depends on the speed, the time of
travel, and direction of motion of the train.
Correct responses:
- Distance Train A is from the city: 750 - 75·t
- Distance Train B is from the city: 50·t
- After six hours, the two trains are the same distance from the city
- At that time both trains will be 300 miles away
1) From the time of departure of Train B to just before 6 hours after Train B's departure; 0 ≤ t < 6 hours
2) At time period, t > 6 hours
3) 250 miles
Method used to find the above response
Given:
The distance of train A from the city = 750 miles
Speed of train A = 75 mph
Time at which Train B leaves the city = When Train A is 750 miles from the city
Speed of Train B = 50 mph
Solution:
The equations are;
- Distance of Train A from the city is; x₁ = 750 - 75·t
- Distance of Train B from the city is x₂ = 50·t
When the train are the same distance from the city, we have;
750 - 75·t = 50·t
750 = 50·t + 75·t = 125·t
Therefore;
- [tex]t = \mathbf{\dfrac{750}{125}} = 6[/tex]
The time it takes the two trains to be the same distance from the city is 6 hours.
Which gives;
- After 6 hours, the two trains are the same distance from the city.
The distance the trains will be after 6 hours is therefore;
750 - 75 × 6 = 300
The distance of the trains from the city after 6 hours = 300 miles
Therefore, we have;
- At that time both trains will be 300 miles away
1) The time period Train A is further from the city is before the first 6 hours elapse; 0 hours ≤ t < 6 hours
2) The Train B is further from the city after 6 hours of its departure from the city; t > 6 hours
3) The distance of Train A from the city after 4 hours is given as follows;
x₁ = 750 - 75 × 4 = 450
x₁ = 450 miles
The distance of Train B from the city after 4 hours is; x₂ = 50 × 4 = 200
x₂ = 200 miles
Therefore;
- The distance between the trains after 4 hours = 450 miles - 200 miles = 250 miles
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