Answer:
292.75mL
Step-by-step explanation:
From the ideal gas equation
PV= nRT
With each symbols having standard meaning
For pressure remaining constant the equation for two states can be written as
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
Given V_1 = 300mL, T_1 = 17° C = 290K and T_2 = 10°C or 283K
Now plugging values in above equation to find V_2
[tex]\frac{300}{290} =\frac{V_2}{283}\\V_2 =\frac{300}{290}\times283 = 292.75mL[/tex]
Therefore, the volume at 10 degrees Celsius = 292.75mL
