A certain resistance thermometer reads 14. 5 Ω in pure melting ice and 18. 5 Ω in steam at standard atmospheric pressure. What will be its resistance at room temperature of 27. 0 o C ?

Respuesta :

The resistance of the thermometer at the given temperature is 15.58 ohms.

Resistance of the thermometer

The resistance of the thermometer can be determined by applying method of interpolation as shown below;

[tex]\frac{R_\theta - R_0}{R_{100} - R_0} = \frac{\theta -0}{100 - 0}[/tex]

where;

  • Rθ is the resistance of the thermometer at 27⁰C
  • R100 is the resistance at steam temperature
  • R0 is the ice temperature

[tex]\\\\\frac{R_\theta - 14.5}{18.5 - 14.5} = \frac{27}{100} \\\\\frac{R_\theta - 14.5}{4} = \frac{27}{100}\\\\100R_\theta - 1450 = 108\\\\100R_\theta = 1558\\\\R_\theta = 15.58 \ ohms[/tex]

Thus, the resistance of the thermometer at the given temperature is 15.58 ohms.

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