Answer:
The correct answer is "0.32 mL".
Explanation:
The given values are:
Density of gold bar,
d = 19.3 g/mL
Mass of gold bar,
m = 6.3 grams
Now,
The volume will be:
⇒ [tex]Density = \frac{Mass}{Volume}[/tex]
or,
⇒ [tex]Volume=\frac{Mass}{Density}[/tex]
On substituting the values, we get
⇒ [tex]=\frac{6.3 \ g}{19.3 \ g/mL}[/tex]
⇒ [tex]=0.32 \ mL[/tex]
