Respuesta :

Nayefx

Answer:

[tex] \huge \boxed{ \boxed{ \red{x = - 7}}}[/tex]

Step-by-step explanation:

to understand this

you need to know about:

  • equation
  • PEMDAS

let's solve:

  1. [tex] \sf distribute : \\ \frac{3 x+ 63}{4} = 10\frac{1}{2} [/tex]
  2. [tex] \sf simplify \: mixed \: fraction : \\ \frac{3x + 63}{4} = \frac{21}{2} [/tex]
  3. [tex] \sf cross \: multipication : \\ 2(3x + 63) = 84[/tex]
  4. [tex] \sf distribute \: 2 : \\ 6x + 126 = 84[/tex]
  5. [tex] \sf cancel \: 126 \: from \: both \: sides : \\ 6x + 126 - 126 = 84 - 126 \\ 6x = - 42[/tex]
  6. [tex] \sf divide \: both \: sides \: by \: 6 : \\ \frac{6x}{6} = \frac{ - 42}{6} \\ \bcancel{\frac{6x}{6} } = \frac{ \cancel{ - 42} \: ^{ - 7} }{ \cancel{ \: 6}} \\ \therefore \: x = - 7[/tex]
msm555

Step-by-step explanation:

Solution given;

[tex] \frac{3}{4} (x + 21) = 10 \frac{1}{2 } \\ 3x + 63 = \frac{21}{2} \times 4 \\ 3x = 42 - 63 \\ x = \frac{ - 21}{3} \\ x = - 7[/tex]

:.x=-7 is your answer.

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