WILL GIVE BRAINLIEST IF YOU USE LAW OF SINES CORRECTLY
Please solve using the law of sines.
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Answer: I know this is an old question, but in case you still don't know how to do Law of Sine here's how you would have solved it. (P.S. I wasn't sure which part of the triangle the problem was looking for, so I solved for all parts)
Step-by-step explanation:
Answer:
[tex]\displaystyle 7,7[/tex]
Step-by-step explanation:
Use the Law of Sines to find the length of the second edge:
Solving for Angles
[tex]\displaystyle \frac{sin\angle{C}}{c} = \frac{sin\angle{B}}{b} = \frac{sin\angle{A}}{a}[/tex]
Use [tex]\displaystyle sin^{-1}[/tex]towards the end or you will throw your result off!
Solving for Edges
[tex]\displaystyle \frac{c}{sin\angle{C}} = \frac{b}{sin\angle{B}} = \frac{a}{sin\angle{A}}[/tex]
Let us get to wourk:
[tex]\displaystyle \frac{c}{sin\:44} = \frac{11}{sin\:82} \hookrightarrow \frac{11sin\:44}{sin\:82} = c; 7,7163369357... \\ \\ \boxed{7,7 \approx c}[/tex]
I am joyous to assist you at any time.