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The flight path of a plane is a straight line from city J J to city K K. The roads from city J J to city K K take the long way around, traveling 9.4 9.4 miles south and then 15.1 15.1 miles east. How many degrees east of south is the plane's flight path, to the nearest tenth? M ∠ J ≈ ? M∠J≈

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abidemiokin

Answer:

58.1 degrees

Step-by-step explanation:

Given the following

JK = 9.4miles (towards south) negative y axis

If the move 15.1 miles towards east (that will be towards the positive x axis)

Using the SOH CAH TOA identity

opposite= 15.1 miles(side facing m<J)

adjacent= JK = 9.4miles

tan theta = opposite/adjacent

tan m<J = 15.1/9.4

tan m<J = 1.6063

m<J = arctan (1.6063)

m<J = 58.09 degrees

Hence the measure of m<J to the nearest tenth is 58.1 degrees

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