Answer:
the answer is =-3±[tex]\sqrt{281}[/tex]/2
Step-by-step explanation:
Answer:
[tex]\bold{p_1\approx6.88\ ,\qquad p_2\approx-9.88}[/tex]
Step-by-step explanation:
[tex]p^2+3p-28=40\\\\p^2+3p-68=0\\\\a=1\,,\ b=3\,,\ c=-68\\\\\\p=\dfrac{-3\pm\sqrt{3^2-4\cdot1\cdot(-68)}}{2\cdot1}=\dfrac{-3\pm\sqrt{281}}{2}\\\\p_1\approx6.88\ ,\qquad p_2\approx-9.88[/tex]
