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A circular wire loop of radius 15.0 cm carries a current of 2.60
a. it is placed so that thenormal to its plane makes an angle of 41.0◦with a uniform magnetic field of magnitude12.0 t. (a) calculate the magnitude of the magnetic dipole moment of the loop. (b)what is the magnitude of the torque acting on the loop?

Respuesta :

jushmk
Part (a): Magnetic dipole moment

Magnetic dipole moment = IA, I = Current, A = Area of the loop
Then,
Magnetic dipole moment = 2.6*π*0.15^2 = 0.184 Am^2

Part (b): Torque acting on the loop
T = IAB SinФ, where B = Magnetic field, Ф = Angle
Then,
T = Magnetic dipole moment*B*SinФ = 0.184*12*Sin 41 = 1.447 Nm

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