Answer:
See proof below
Step-by-step explanation:
sin a + cos a/sec a+ cosec a= sin a* cos a
(sina+cosa)/(sec a + cosec a)
In trigonometry identity
seca = 1/cos a
cosec a = 1/sin a
Substituted into the given expression
= sina + cosa/(1/cosa+1/sina)
Find the LCM
= sina + cosa /(sina+cosa/sinacosa)
= (sina+cosa) * sinacosa/(sina + cosa)
= sinacosa (RHS)
This shows that the equation is true
