Answer:
[tex]D=1.15608m[/tex]
Explanation:
From the question we are told that
Radius of chute [tex]r=0.57[/tex]
Magnitude of radial acceleration [tex]a_r=12.4m/s^2[/tex]
Generally the equation for the centripetal acceleration is mathematically given by
[tex]a_r=\frac{v^2}{R}[/tex]
[tex]v=\sqrt{0.57*12.4}[/tex]
[tex]v=2.4m/s[/tex]
Generally the equation for the motion is mathematically given by
[tex]S= ut +0.5at^2[/tex]
[tex]t^2= \frac{S-ut}{1/2a}[/tex]
[tex]t^2= \frac{(2*0.57)-0}{1/2*9.8}[/tex]
[tex]t^2= 0.232[/tex]
[tex]t= \sqrt{ 0.232}[/tex]
[tex]t= 0.4817sec[/tex]
Generally the equation for the distance traveled is mathematically given by
[tex]D=vt[/tex]
[tex]D=0.4817sec*2.4m/s[/tex]
[tex]D=1.15608m[/tex]
