Answer:
[tex]S = 678.71km/hr[/tex]
Explanation:
The question has missing details. See comment for complete question
Given
[tex]d = 2,742km[/tex] --- distance
[tex]t_1 =4.33hr[/tex] --- time spent to Oregon
[tex]t_2 =3.75[/tex] -- time spent back to St. Louis
Required
Calculate the average speed
First, we calculate the total distance of the trip.
Because it is a "to and fro" trip and the airplane passes the same route, the total distance D is:
[tex]D = 2*d[/tex]
[tex]D = 2*2742km[/tex]
[tex]D = 5484km[/tex]
The total time taken (T) is:
[tex]T = t_1 + t_2[/tex]
[tex]T = 4.33hr + 3.75hr[/tex]
[tex]T = 8.08hr[/tex]
The average speed (S) is then calculated as:
[tex]S = \frac{D}{T}[/tex]
[tex]S = \frac{5484km}{8.08hr}[/tex]
[tex]S = 678.71km/hr[/tex]
The average speed for the trip is approximately 678.71
