Answer:
see below
Step-by-step explanation:
I assume when you write x3 you mean
[tex] {x}^{3} [/tex]
so the expressions is:
[tex](6{x}^{3} - 5x) + (2 {x}^{3} + {x}^{2 } + 10x)[/tex]
we can combine like terms
[tex]6 {x}^{3} + 2 {x}^{3} + {x}^{2} - 5x + 10x[/tex]
[tex]8 {x}^{3} + {x}^{2} + 5x[/tex]
the last thing we can do is factor out x because all 3 pieces have at least one x in them
[tex]x( 8{x}^{2} + x + 5)[/tex]
