Answer: The molar concentration of oxygen gas is [tex]8.84\times 10^{-4}mol/L[/tex]
Explanation:
To calculate the molar solubility, we use the equation given by Henry's law, which is:
[tex]C_{O_2}=K_H\times p_{O_2}[/tex]
where,
[tex]K_H[/tex] = Henry's constant = [tex]1.3\times 10^{-3}mol/L.atm[/tex]
[tex]C_{O_2}[/tex] = molar solubility of oxygen gas = ?
[tex]p_{O_2}[/tex] = partial pressure of oxygen gas = 0.68 atm
Putting values in above equation, we get:
[tex]C_{O_2}=1.3\times 10^{-3}mol/L.atm\times 0.68atm\\\\C_{O_2}=8.84\times 10^{-4}mol/L[/tex]
Hence, the molar concentration of oxygen gas is [tex]8.84\times 10^{-4}mol/L[/tex]
