Respuesta :

10n31y

[tex]ek = \frac{1}{2}m {v}^{2} [/tex]

[tex]ek = \frac{1}{2}(50) {(1)}^{2} [/tex]

[tex]ek = \frac{1}{2}(50)[/tex]

[tex]ek = 25j[/tex]

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I'm not really sure but I do know that it's not 0 because the object is still moving, even if it's only moving at 1 m/s.