Respuesta :

mariamalsuwaidi
Answer:
S₇ = 672

Step-by-step explanation:
If there are 7 consecutive numbers and the largest is 99, then there are 6 smaller

consecutive numbers:
Smallest number = 99-6 = 93

The sequence is 93, 94, 95, 96, 97, 98, 99.
Where:

a₁ = 93
an = 99
n = 7
Sum of the sequence:

Sn = n/2(a₁ + an)
S₇ = 7/2 (93 + 99)
S₇ = 7/2 (192)
S₇ = 7(96)
S₇ = 672
hluo

Answer:

S₇ = 672

Step-by-step explanation:

If there are 7 consecutive numbers and the largest is 99, then there are 6 smaller consecutive numbers:

Smallest number = 99-6 = 93

The sequence is 93, 94, 95, 96, 97, 98, 99.

Where:

a₁ = 93

an = 99

n = 7

Sum of the sequence:

Sn = n/2(a₁ + an)

S₇ = 7/2 (93 + 99)

S₇ = 7/2 (192)

S₇ = 7(96)

S₇ = 672

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