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An arrow is fired at 5.20 m s−1 at an angle of 22.0° above the horizontal. Find the horizontal component of the initial velocity, expressing your answer in m s−1 to 2d.P.\

Respuesta :

lublana

Answer:

[tex]4.82ms^{-1}[/tex]

Explanation:

We are given that

Initial velocity, u=5.20m/s

[tex]\theta=22^{\circ}[/tex]

We have to find the horizontal component of the initial velocity.

We know that

Horizontal component of velocity=[tex]ucos\theta[/tex]

Using the formula

Horizontal component of the initial velocity=[tex]5.2cos22^{\circ}[/tex]

Horizontal component of the initial velocity=[tex]5.2\times 0.9272[/tex]

Horizontal component of the initial velocity=[tex]4.82ms^{-1}[/tex]

Hence, the horizontal component of the initial velocity=[tex]4.82ms^{-1}[/tex]

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