A 4.0 kg box is released from rest on a frictionless ramp. The box slides from the ramp onto a rough horizontal
surface with a friction coefficient per = 0.50. The box slides 2.0 m horizontally until it stops.

Respuesta :

Answer:

1.0m

Explanation:

khan

Answer:

0.99932188871837 rounded to 2 significant figures is 1.00m or 1.0m

Explanation:

Step 1 - First calculate the force with the formula: Force = mass ×  acceleration due to gravity/ (F=mg) {g= 9.8m/s²}

4.0kg × 9.8m/s² = 39.2 Newtons

Step 2 - Then calculate the Kinectic power with the following procedure:

Kinectic force = the coefficient of Kf × mg

0.50μ × 39.2 N = 19.6 Newtons of Kinectic force

Step 3 - Use the equation for Work that is = F×d; use the value of Kf and multiply it by the given distance

W = 19.6 N × 2.0m = 39.2 Joules of energy

↓Remember that the product of Work is Energy (W=E) and that in some cases, we can set W as = kinetic energy ( [tex]\frac{1}{2}[/tex]mass×velocity²) or as = gravitational potential energy (mass *acceleration due to gravity*height)

↑Since the unknown variable that we are told to find is 'height', let's use the second formula to help us solve the problem, where we said that GPE = mgh / PEg = mgh

Step 4 - Find the missing height using the formula, Energy gained from (W = mgh), by rewriting (mgh) to solve for h

39.2 J of E = 4.0kg × (9.8 m/s² × h)

h = [tex]\frac{PEg}{mg}[/tex]

h = [tex]\frac{39.2N}{9.8m/s{2} times 4.0kg}[/tex]  

Height of box on-ramp = 1.0m