The half-life of C-14 is approximately 5730 years. This means that the quantity contained in the sample becomes half of its original value after 5730 years. After another 5730 years, the quantity becomes 1/4 of its original value, and so on.
In our problem, the sample shows only one-fourth of its estimated original quantity, this means that its age is twice 5730 years:
[tex]t=5730 y+5730 y=11460 y[/tex]
