Consider the following reaction:
10 KCIO3 + 3 P4 → 3 P4010 + 10 KCI
Given 30 moles of P4 and 86 moles of KCIO3, which would act as the limiting reactant?

Respuesta :

Answer: [tex]KClO_3[/tex] is the limiting reactant in the given reaction.

Explanation:

Limiting reagent is defined as the chemical specie which gets totally consumed in the reaction and the formation of product is dependent on this reagent.

We are given:

Moles of [tex]P_4[/tex] = 30 moles

Moles of [tex]KClO_3[/tex] = 86 moles

The given chemical equation follows:

[tex]10KCIO_3+3P_4\rightarrow 3P_4O_{10}+10KCI[/tex]

By Stoichiometry of the reaction:

If 10 moles of [tex]KClO_3[/tex] reacts with 3 moles of [tex]P_4[/tex]

Then, 86 moles of [tex]KClO_3[/tex] will react with = [tex]\frac{3}{10}\times 86=25.8moles[/tex] of [tex]P_4[/tex]

As, given amount of [tex]P_4[/tex] is more than the required amount. So, it is considered as an excess reagent.

Therefore, [tex]KClO_3[/tex] is considered as a limiting reactant because it limits the formation of product.