Answer:
5 000 000 (5 million atoms)
Explanation:
Let us assume that a vanadium atom has a spherical shape.
diameter of a sphere = 2 x radius of the sphere
Thus,
Radius of a vanadium atom = 130 pm
= 130 x [tex]10^{-12}[/tex] m
The diameter of a vanadium atom = 2 x radius
= 2 x 130 x [tex]10^{-12}[/tex]
= 260 x [tex]10^{-12}[/tex] m
Given a distance of 1.30 mm = 1.30 x [tex]10^{-3}[/tex] m,
The number of vanadium atoms required to span the distance = [tex]\frac{1.3*10^{-3} }{260*10^{-12} }[/tex]
= 5000000
Therefore, the number of vanadium atom that would span a distance of 1.30 mm is 5 million.
