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A point charge (q1) has a magnitude of 3.0 x10-6 C. A second charge (q2) has a magnitude of -1.5 x10-6 C and is located 0.12 m from the first charge. Determine the electrostatic force each charge exerts on the other.

Respuesta :

Answer:2.81 N

Explanation:

Given

[tex]q_1=3\times 10^{-6}\ C\\q_2=-1.5\times 10^{-6}\ C[/tex]

distance between them r=0.12 m

Electrostatic force is [tex]F=\frac{kq_1q_2}{r^2}[/tex]

Putting values

[tex]F=\dfrac{9\times 10^9\times (3\times 10^{-6})\times (-1.5\times 10^{-6})}{0.12^2}\\F=2.81\ N[/tex]

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