contestada

A 7.03 nC charge is located 1.75 m from a 4.26 nC point charge. (a) Find the magnitude of the electrostatic force that one charge exerts on the other.

Respuesta :

Given that,

Charge, q₁ = 7.03 nC

Charge, q₂ = 4.26 nC

Distance, r = 1.75 m

To find,

The magnitude of the electrostatic force that one charge exerts on the other.

Solution,

The force between two charges at a distance is given by the formula as formula :

[tex]F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times 7.03\times 10^{-9}\times 4.26\times 10^{-9}}{(1.75)^2}\\\\=8.8\times 10^{-8}\ N[/tex]

So, the required force is [tex]8.8\times 10^{-8}\ N[/tex].