Answer:
D option is correct
Leading variables=[tex]X_1,X_2[/tex]
Free variables =none
Step-by-step explanation:
From the question we are told that
The Equation is
[tex]-4x_1 + 2x_2 = -3[/tex]
[tex]6x2 = 0[/tex]
The matrix is represented as
[tex]\begin{bmatrix} -4 & 2 & -3 \\0& 6 & 0\\\end{bmatrix}[/tex]
This being the matrix form shows the system already in echelon for
Therefore D option is correct
Leading variables=[tex]x_1,x_2[/tex]
Free variables =none