Answer:
Step-by-step explanation:
let the eq. of parabola be
y=ax²+bx+c
∵ (0,3),(1,2),(2,3) lie on it.
3=0+0+c
so c=3
and 2=1a+1b+c
2=a+b+3
a+b=-1
3=4a+2b+c
3=4a+2b+3
4a+2b=0
or 2a+b=0
b=-2a
substituting
a+(-2a)=-1
-a=-1
a=1
b=-2a=-2×1=-2
so eq. of parabola is
y=x²-2x+3
