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10.0 grams of a gas occupies 12.5 liters at a pressure of 42.0 mm Hg. What is the volume when the pressure has increased to 75.0 mm Hg? 6.72 L 7.00 L 22.3 L 0.143 L

Respuesta :

Answer:  7.00 L

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

[tex]P\propto \frac{1}{V}[/tex]     (At constant temperature and number of moles)

[tex]P_1V_1=P_2V_2[/tex]  

where,

[tex]P_1[/tex] = initial pressure of gas  = 42.0 mm Hg

[tex]P_2[/tex] = final pressure of gas  = 75.0 mm Hg

[tex]V_1[/tex] = initial volume of gas   = 12.5 L

[tex]V_2[/tex] = final volume of gas  = ?

[tex]42.0\times 12.5=75.0\times V_2[/tex]  

[tex]V_2=7.00L[/tex]

Therefore, the volume  when the pressure has increased to 75.0 mm Hg is 7.00 L

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